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East Troy is a village in Walworth County, Wisconsin, United States. The population was 5,673 at the 2020 census. The village is surrounded by the Town of East Troy, with a small portion extending into the adjacent Town of Troy. == Geography == East Troy is located at 42°48′N 88°24′W (42.7868, -88.4036). According to the United States Census Bureau, the village has a total area of 4.51 square miles (11.68 km2), of which, 4.47 square miles (11.58 km2) of it is land and 0.04 square miles (0.10 km2) is water. == Demographics == === 2010 census === As of the census of 2010, there were 5673 people, 1,737 households, and 1,125 families living in the village. The population density was 957.7 inhabitants per square mile (369.8/km2). There were 1,866 housing units at an average density of 417.4 per square mile (161.2/km2). The racial makeup of the village was 95.9% White, 0.4% African American, 0.5% Native American, 0.6% Asian, 0.1% Pacific Islander, 1.1% from other races, and 1.4% from two or more races. Hispanic or Latino of any race were 4.0% of the population.